A) \[2\times {{10}^{4}}J\]
B) \[2\times 100J\]
C) \[2\times {{10}^{11}}J\]
D) \[2\times {{10}^{15}}J\]
Correct Answer: A
Solution :
Work done \[W=p({{V}_{2}}-{{V}_{1}})\] Given, \[p=2\times {{10}^{5}}N/{{m}^{2}},\,\,{{V}_{1}}=50\times {{10}^{-3}}\,\,{{m}^{3}}\] \[{{V}_{2}}=150\times {{10}^{-3}}{{m}^{3}}\] \[\therefore \,\,\,W=2\times {{10}^{5}}(150-50){{10}^{-3}}\] \[W=2\times {{10}^{5}}\times 100\,\times {{10}^{-3}}\] \[W=2\times {{10}^{4}}J\]
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