question_answer

A voltmeter of resistance\[998\Omega \]is connected across a cell of emf\[2\,\,V\]and internal resistance\[2\Omega \]. The potential difference across the voltmeter is

A) \[1.99\,\,V\]                      

B) \[3.5\,\,V\]

C) \[5\,\,V\]                            

D)        \[6\,\,V\]

Correct Answer: A

Solution :

From Ohms law                 \[i=\frac{E}{R+r}=\frac{2}{998+2}=2\times {{10}^{-3}}A\] Potential difference across the voltmeter is                 \[V=iR=(2\times {{10}^{-3}})\times 998\]                 \[=1996\,V\]