Manipal Engineering Manipal Engineering Solved Paper-2012

  • question_answer
    An atom of mass M which is in the state of rest emits a photon of wavelength\[\lambda \]. As a result, the atom will deflect with the kinetic energy equal to (\[h\]is Plancks constant)

    A) \[\frac{{{h}^{2}}}{M{{\lambda }^{2}}}\]                

    B) \[\frac{1}{2}\frac{{{h}^{2}}}{M{{\lambda }^{2}}}\]

    C) \[\frac{h}{M\lambda }\]                              

    D)        \[\frac{1}{2}\frac{h}{M\lambda }\]

    Correct Answer: B

    Solution :

    Momentum of photon, \[p=\frac{h}{\lambda }\] Kinetic energy of photon of mass\[M\],\[K=\frac{{{p}^{2}}}{2M}\] or            \[K=\frac{{{h}^{2}}}{2M{{\lambda }^{2}}}\]


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