A) \[H{{g}_{2}}C{{l}_{2}}\]
B) \[PbC{{l}_{2}}\]
C) \[H{{g}_{2}}C{{l}_{2}}\]and\[PbC{{l}_{2}}\]
D) \[HgC{{l}_{2}}\]and\[PbC{{l}_{2}}\]
Correct Answer: C
Solution :
\[Hg_{2}^{2+}\]and\[P{{b}^{2+}}\]have been placed in I group of basic radicals as their\[{{K}_{sp}}\]less than the II group ions\[(H{{g}^{2+}},\,\,C{{d}^{2+}})\]. Hence, only these will precipitate.You need to login to perform this action.
You will be redirected in
3 sec