A) 1
B) 3
C) 5
D) 7
Correct Answer: B
Solution :
\[\sin x\cdot \cos y=1\] \[\Rightarrow \] \[\sin x=1,\,\,\cos y=1\] or \[\sin x=-1,\,\,\cos y=-1\] if \[\sin x=1,\,\,\cos y=1\] \[\Rightarrow x=\frac{\pi }{2},\,\,y=0,\,\,2\pi \] if \[\sin x=-1,\,\,\cos y=-1\Rightarrow x=\frac{3\pi }{2},\,\,y=\pi \] Thus possible ordered pairs are \[\left( \frac{\pi }{2},\,\,0 \right),\,\,\left( \frac{\pi }{2},\,\,2\pi \right),\,\,\left( \frac{3\pi }{2},\,\,\pi \right)\]
You need to login to perform this action.
You will be redirected in
3 sec
