A) A tautology
B) A contradiction
C) Both a tautology and a contradiction
D) Neither a tautology nor a contradiction
Correct Answer: B
Solution :
\[(p\wedge \tilde{\ }q)(\tilde{\ }p\wedge q)=(p\wedge \tilde{\ }p)\wedge (\tilde{\ }q\wedge q)\] \[=f\wedge f=f\] (By using associative laws and commutative laws.) \[\therefore \]\[(p\wedge \tilde{\ }q)\wedge (\tilde{\ }p\wedge q)\]is a contradiction.
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