A) \[4{{E}_{n}}\]
B) \[{{E}_{n}}/4\]
C) \[2{{E}_{n}}\]
D) \[{{E}_{n}}/2\]
Correct Answer: A
Solution :
\[E=\frac{-m{{z}^{2}}{{e}^{4}}}{8{{\varepsilon }_{0}}{{h}^{2}}}\cdot \frac{1}{{{n}^{2}}}\] \[{{Z}_{H}}=1\] \[{{Z}_{He}}=2\] \[\frac{{{E}_{H}}}{{{E}_{He}}}=\frac{Z_{H}^{2}}{Z_{He}^{2}}=\frac{1}{4}\] \[{{E}_{H}}=\frac{Z_{H}^{2}}{Z_{He}^{2}}=\frac{2}{4}\] \[{{E}_{He}}=4{{E}_{H}}\] \[{{E}_{H}}={{E}_{n}}\] \[{{E}_{He}}=4{{E}_{n}}\]
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