A) \[\left( \frac{43}{29} \right)\lambda \]
B) \[\left( \frac{42}{28} \right)\lambda \]
C) \[\left( \frac{9}{4} \right)\lambda \]
D) \[\left( \frac{4}{9} \right)\lambda \]
Correct Answer: C
Solution :
As, \[\sqrt{V}=a(Z-b)\] \[\sqrt{V}=a(Z-1)\] \[V={{a}^{2}}{{(Z-1)}^{2}}\] \[\frac{C}{\lambda }={{a}^{2}}{{(Z-1)}^{2}}\] \[\lambda =\frac{c}{{{a}^{2}}{{(Z-1)}^{2}}}\] \[z=43\], wavelength\[=\lambda \] \[\lambda =\frac{c}{{{a}^{2}}{{(43-1)}^{2}}}\] \[\lambda =\frac{c}{{{a}^{2}}\times 42}\] for\[z=29\], wavelength\[=\lambda \] \[\lambda =\frac{C}{{{a}^{2}}{{(29-1)}^{2}}}\] \[\lambda =\frac{c}{28{{a}^{2}}}\] \[\frac{\lambda }{\lambda }=-{{\left( \frac{42}{28} \right)}^{2}}={{\left( \frac{3}{2} \right)}^{2}}\] \[\lambda =\left( \frac{9}{4} \right)\lambda \]
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