Manipal Medical Manipal Medical Solved Paper-2000

  • question_answer
    A potential energy of satellite, having mass m and rotating at height of\[6.4\times {{10}^{6}}m\]from the earth surface will be:

    A)  \[-0.5\,mg{{R}_{e}}\]      

    B)  \[-1.5mg{{R}_{e}}\]

    C)  \[-0.67mg{{R}_{e}}\]      

    D)  none of these

    Correct Answer: A

    Solution :

     Here: Mass of the satellite \[=m\] Height of the satellite from the earth \[h=6.4\times {{10}^{6}}m\] Gravitation potential energy of the satellite at a height h is given by, \[U=-\frac{G{{M}_{e}}m}{{{R}_{e}}+h}=-\frac{gR_{e}^{2}m}{2{{R}_{e}}}\] \[=-\frac{g{{R}_{e}}m}{2}=-0.5\,mg\,{{R}_{e}}\] (where\[G{{M}_{e}}=gR_{e}^{2}\]and\[h={{R}_{e}}\])


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