A) \[\frac{20}{19}\Omega \]
B) \[\frac{19}{20}\Omega \]
C) \[\frac{19}{10}\Omega \]
D) \[\frac{10}{19}\Omega \]
Correct Answer: B
Solution :
Here: Resistance of the 1st resistors \[{{R}_{1}}=2\,\Omega \] Resistance of the IInd resistor\[{{R}_{2}}=4\,\Omega \] Resistance of the IIIrd resistor\[{{R}_{3}}=5\,\Omega \] The relation for the equivalent resistance\[{{R}_{eq}}\]of the circuit in parallel combination \[\frac{1}{{{R}_{eq}}}=\frac{1}{{{R}_{1}}}+\frac{1}{{{R}_{2}}}+\frac{1}{{{R}_{3}}}\] \[=\frac{1}{2}+\frac{1}{4}+\frac{1}{5}=\frac{19}{20}\] Or \[{{R}_{eq}}=\frac{20}{19}\Omega \]
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