A) \[N{{H}_{2}}OH\]
B) \[NH_{4}^{+}\]
C) \[N{{H}_{3}}\]
D) \[NH_{2}^{+}\]
Correct Answer: B
Solution :
The conjugate acid of\[N{{H}_{3}}\]is\[NH_{4}^{+}\]ion. \[\underset{Acid}{\mathop{NH_{4}^{+}}}\,+\underset{Base}{\mathop{{{H}_{2}}O}}\,\underset{Base}{\mathop{N{{H}_{3}}}}\,+\underset{Acid}{\mathop{{{H}_{2}}{{O}^{+}}}}\,\]
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