A) \[22400\text{ }c{{m}^{3}}\]
B) \[6.02\times {{10}^{-23}}c{{m}^{3}}\]
C) \[3.0\times {{10}^{-23}}c{{m}^{3}}\]
D) \[11200\text{ }c{{m}^{3}}\]
Correct Answer: C
Solution :
We know that volume occupied by one molecule of water \[=\frac{mass\text{ }of\text{ }water}{density\text{ }of\text{ }water}\] mass of water\[=\frac{molecular\text{ }weight}{6.02\times {{10}^{23}}}\] \[=\frac{18}{6.02\times {{10}^{23}}}\] \[=3.0\times {{10}^{-23}}\] \[\therefore \]volume\[=\frac{3.0\times {{10}^{-23}}}{1}\] \[=3.0\times {{10}^{-23}}c{{m}^{-3}}\]
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