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Manipal Medical Manipal Medical Solved Paper-2000

  • question_answer
    If\[|\overrightarrow{A}\times \overrightarrow{B}|=|\overrightarrow{A}.\overrightarrow{B}|\]then the angle between\[\overrightarrow{A}\]and \[\overrightarrow{B}\]will be:

    A)  \[90{}^\circ \]            

    B)  \[60{}^\circ \]

    C)  \[45{}^\circ \]             

    D)  \[30{}^\circ \]

    Correct Answer: C

    Solution :

     The moduli! of cross and dot product of vector \[\overrightarrow{A}\]and\[\overrightarrow{B}\]are\[AB\text{ }sin\text{ }\theta \]and\[AB\text{ cos }\theta \] respectively.   Therefore,   the   given condition, \[AB\sin \theta =ABcos\theta \] or       \[tan\text{ }\theta =1\]or \[\theta =45{}^\circ \]


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