A) unchanged
B) halved
C) doubled
D) quadrupled
Correct Answer: A
Solution :
Here: Initial length of the conductor \[{{l}_{1}}=l\] Final length of the conductor \[{{l}_{2}}=2l\] Initial cross-sectional area\[{{A}_{1}}=A\] Final corss-sectional area\[{{A}_{2}}=2A\] The resistance of conductors given by, \[R=\rho \frac{l}{A}\propto \frac{l}{A}\] As both the length and area are doubled. Hence, there will be no change in the resistance of the conductor and so it will remain unchanged.
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