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Manipal Medical Manipal Medical Solved Paper-2001

  • question_answer
    A capacitor is charged to a potential of difference of 400 volt and its plates acquire charge of 0.2 coulomb. When the capacitor is discharged, the energy released, is:

    A)  40J            

    B)  20J

    C)  80J            

    D)  60J

    Correct Answer: A

    Solution :

     Potential difference \[V=400\text{ }V\] Charge      \[Q=0.2C\] The energy released from the capacitor is given by, \[E=\frac{1}{2}QV=\frac{1}{2}\times 0.2\times 400\] \[=40\,J\]


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