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Manipal Medical Manipal Medical Solved Paper-2001

  • question_answer
    The coefficient of mutual inductance when magnetic flux changes by\[5\times {{10}^{-2}}\] weber and changes in current is 0.01 A, will be:

    A)  10H           

    B)  5H

    C)  2.5H            

    D)  7.5H

    Correct Answer: B

    Solution :

     Here: Change in magnetic flux \[\phi =5\times {{10}^{-2}}Wb\] Change in current \[i=0.01\text{ }A\] The coefficient of mutual inductance is given by, \[M=\frac{Q}{i}=\frac{5\times {{10}^{-2}}}{0.01}\] \[=5\text{ }H\]


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