A) 184 kJ
B) \[-184kJ\]
C) 46 kJ
D) \[-46kJ\]
Correct Answer: B
Solution :
The enthalpy formation of ammonia is\[-46\text{ }kJ/\]mol. Therefore, in the reaction \[2{{N}_{2(g)}}+6{{H}_{2(g)}}\xrightarrow[{}]{{}}4N{{H}_{3(g)}}\] four molecules of ammonia are formed \[\therefore \]Enthalpy formation \[=4\times (-)46=-184\text{ }kJ.\]You need to login to perform this action.
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