A) \[HCl<HBr<HF<HI\]
B) \[HF<HCl<HBr<HI\]
C) \[HI<HBr<HCl<HF\]
D) \[HBr<HCl<HF<HI\]
Correct Answer: B
Solution :
The increasing order of reducing power of halogen acid is \[HF<HCl<HBr<HI\] The reason is that by increasing the size of halogen atom the bond strength of\[H-X\]bond decreases. Thus the case of hydrogen atom increases and hence reducing power increases.
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