A) 1.5094
B) 1.3056
C) 0.7849
D) 2.425
Correct Answer: A
Solution :
Here: Refracting angle\[A=60{}^\circ ,\]minimum deviation\[\delta m=38{}^\circ \]The refractive index is given by the formula \[R.I.=\frac{\sin \frac{A+\delta m}{2}}{\sin \frac{A}{2}}=\frac{\sin \frac{60{}^\circ +38{}^\circ }{2}}{\sin \frac{60{}^\circ }{2}}\] \[=\frac{\sin 49{}^\circ }{\sin 30{}^\circ }=\frac{0.7547}{0.5}=1.5094\]You need to login to perform this action.
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