A) (A - Z) and (Z - 1)
B) (A - Z) and (Z - 2)
C) (A -4) and (A -2)
D) (A-4) and (Z - 1)
Correct Answer: D
Solution :
When an a-particle is emitted, mass number of nuclide X is reduced to 4, and its charge number is reduced to 2, But when a\[\beta -\] particle is emitted, mass number of remains the same and its charge number is increased by 1. Hence, the resulting nuclide has alomic mass A - 4 and atomic number Z - 1.You need to login to perform this action.
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