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Manipal Medical Manipal Medical Solved Paper-2002

  • question_answer
    A boy of 50 kg is standing in a left moving down with an acceleration\[9.8\text{ }m/{{s}^{2}}\]. The apparent weight of the boy is:

    A)  \[\frac{50}{9.8}N\]     

    B)  \[50\times 9.8N\]

    C)  50 N             

    D)  zero

    Correct Answer: D

    Solution :

     Mass of the boy \[m=50\] Acceleration of lift (downwards) \[a=9.8\text{ }m/{{s}^{2}}\] The apparent weight of the boy when the lift is moving downwards \[W=m(g-a)=50(9.8-9.8)=0\]


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