A) \[12\,\pi \]
B) \[8\,\pi \]
C) \[5\,\pi \]
D) \[2\,\pi \]
Correct Answer: C
Solution :
Here: Mutual inductance between two coils\[M=0.005\text{ }H\]. Peak current \[{{I}_{0}}=10\text{ }amp\] Angular frequency \[\omega =100\,\pi \,rad/\sec \] The current \[I={{I}_{0}}\sin \omega t\] Or \[\frac{d}{dt}=\frac{d}{dt}({{I}_{0}}\sin \omega t)\] \[={{I}_{0}}\cos \omega t.\omega \] \[=10\times 1\times 100\pi =1000\text{ }\pi \] Hence, induced emf. is given by \[E=M\times \frac{di}{dt}=0.005\times 1000\times \pi =5\pi V\]
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