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Manipal Medical Manipal Medical Solved Paper-2002

  • question_answer
    A nuclei X with mass number A and charge number Z, disintegrates into one\[\alpha -\]particle and one\[\beta -\]particle. The resulting nuclide R has atomic mass and atomic number, equal to:

    A)  (A - Z) and (Z - 1)

    B)  (A - Z) and (Z - 2)

    C)  (A -4) and (A -2)

    D)  (A-4) and (Z - 1)

    Correct Answer: D

    Solution :

     When an a-particle is emitted, mass number of nuclide X is reduced to 4, and its charge number is reduced to 2, But when a\[\beta -\] particle is emitted, mass number of remains the same and its charge number is increased by 1. Hence, the resulting nuclide has alomic mass A - 4 and atomic number Z - 1.


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