A) 4
B) 8
C) 12
D) 14
Correct Answer: C
Solution :
The millimoles of \[HCl=40\times 0.1=4\] The millimoles of \[NaOH=10\times 0.45=4.5\] The remaining millimoles of \[NaOH=0.5\] Hence, the volume of the solution \[=50\text{ }ml\] Hence, moles of\[NaOH\]in one litre \[=\frac{0.5\times {{10}^{-3}}\times 100}{50}\] \[=1\times {{10}^{-3}}M\] \[\therefore \]\[pOH=-\log (1\times {{10}^{-2}})=2\] \[\therefore \] \[pH=14-2=12\]
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