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Manipal Medical Manipal Medical Solved Paper-2002

  • question_answer
    The resistance of 1 N solution of acetic acid is 250 ohm, when measured in a cell of cell constant\[1.15\text{ }c{{m}^{-1}}\]. The equivalent conductivity in\[oh{{m}^{-1}}\]cm\[equi{{v}^{-1}}\]1N acetic acid is:

    A)  3.8               

    B)  4.6

    C)  9.2             

    D)  12.6

    Correct Answer: B

    Solution :

     We know that conductivity \[=\frac{1}{R}\times cell\text{ }constant=\frac{1.15}{250}\] \[\therefore \]Equivalent conductivity \[=\frac{conductivity\times 100}{N}\] \[=\frac{1.15\times 100}{250\times 0.1}=4.6\]


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