A) 22.5 m
B) 15 m
C) 10 m
D) 5 m
Correct Answer: B
Solution :
Here: Energy of one apple\[=2112\text{ }J\] \[=21\times {{10}^{3}}J\] Efficiency of the boy\[=28%=0.28\] Mass of the boy \[m=40\text{ }kg\] Here the actual energy consumed by the boy is given by as \[=0.28\times 21000=5880\text{ }J\] ...(1) and the energy consumed by the boy in climbing h meter height is given by \[=m\,g\,h=40\times 9.8\times h\,J\] ...(2) Equating equation (1) and (2) we get \[40\times 9.8\times h=5880\,J\] \[h=\frac{5880}{40\times 9.8}=15\,m\]
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