A) 2000 g
B) 1250 g
C) 1000g
D) 600g
Correct Answer: A
Solution :
\[{{t}_{1/2}}=\]10 days\[\Rightarrow \]number of half life in 40 days \[=\frac{40}{10}=4\] Amount left after n half life \[=\frac{1}{{{2}^{n}}}=\frac{1}{{{2}^{4}}}=\frac{1}{16}\] If original amount is\[x,\]then \[\frac{1}{16}x=125\] \[x=\text{ }125\times 16\] \[=2000g.\]
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