A) scattering is reduced at noon
B) refraction of light is minimum at noon
C) rays are incident almost normally
D) the sun is nearer to earth at noon
Correct Answer: C
Solution :
The intensity of illumination is given by \[I=\frac{P\cos \theta }{{{r}^{2}}}\] ...(i) where \[P=\]power of the; source \[r=\]distance between source and point \[\theta =\]angle of incidence when\[\theta =0,\]I will be maximum. Hence the rays from the sun are incident normally on the earth surface.
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