A) 0.4 A
B) 0.3 A
C) 0.2 A
D) 0.1 A
Correct Answer: D
Solution :
From the figure, it is seen that the emfs of the cells are in opposite directions, hence net emf of the cell is\[5-2=3V,\]external resistance in the circuit is \[=10+20=30\,\Omega \] Hence, current in the circuit is given \[i=\frac{V}{R}\] \[=\frac{3}{30}=0.1A\]
You need to login to perform this action.
You will be redirected in
3 sec
