A) \[PV\]
B) \[\frac{R}{\gamma -1}\]
C) \[\frac{PV}{\gamma -1}\]
D) \[\frac{\gamma PV}{\gamma -1}\]
Correct Answer: C
Solution :
The change in internal energy at constant pressure is \[dV=\frac{1}{\gamma -1}({{P}_{2}}{{V}_{2}}-{{P}_{1}}{{V}_{1}})\] \[=\frac{1}{\gamma -1}[P\times 2V-P\times V]\] \[=\frac{PV}{\gamma -1}\]
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