A) \[\lambda =\frac{{{\log }_{10}}2}{{{(T)}_{1/2}}}\]
B) \[\lambda =\frac{{{\log }_{2}}e}{{{(T)}_{1/2}}{{\log }_{10}}e}\]
C) \[\lambda =\frac{{{\log }_{2}}10}{{{(T)}_{1/2}}{{\log }_{2}}e}\]
D) \[\lambda =\frac{{{\log }_{10}}2}{{{(T)}_{1/2}}{{\log }_{10}}e}\]
Correct Answer: D
Solution :
The decay constant is \[\lambda =\frac{0.693}{{{T}_{1/2}}}=\frac{{{\log }_{e}}2}{{{T}_{1/2}}}\] Or \[\lambda =\frac{{{\log }_{10}}2/{{\log }_{10}}e}{{{T}_{1/2}}}\] \[\therefore \] \[\lambda =\frac{{{\log }_{10}}2}{{{\log }_{10}}e\times {{T}_{1/2}}}\]
You need to login to perform this action.
You will be redirected in
3 sec
