Manipal Medical Manipal Medical Solved Paper-2005

  • question_answer
    If the half life of an isotope X is 10 years, its decay constant is:

    A)  \[6.932\text{ }y{{r}^{-1}}\]      

    B)  \[0.6932\text{ }y{{r}^{-1}}\]

    C)  \[0.06932\text{ }y{{r}^{-1}}\]   

    D)  \[0.006932\text{ }y{{r}^{-1}}\]

    Correct Answer: C

    Solution :

     We know that, \[\lambda =\frac{0.693}{{{t}_{1/2}}}\] \[=\frac{0.693}{10}\] \[=0.0693\text{ }y{{r}^{-1}}\]


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