A) \[6C\]
B) \[4C\]
C) \[\frac{3C}{2}\]
D) \[\frac{6C}{11}\]
Correct Answer: D
Solution :
\[\frac{1}{{{C}_{eq}}}=\frac{1}{3C}+\frac{1}{2C}+\frac{1}{C}=\frac{2+3+6}{6C}=\frac{11}{6C}\] \[{{C}_{eq}}=\frac{6C}{11}\]
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