A) \[M{{g}^{2+}}\]
B) \[{{O}^{2-}}\]
C) \[{{F}^{-}}\]
D) \[C{{a}^{2+}}\]
Correct Answer: D
Solution :
\[_{20}Ca=2,8,8,2\] \[C{{a}^{2+}}=2,8,8\] Hence,\[C{{a}^{2+}}\]has 8 electrons each in outermost and penultimate shell.
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