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Manipal Medical Manipal Medical Solved Paper-2005

  • question_answer
    A body initially at rest is moving with uniform acceleration a. Its velocity after n second is\[\upsilon \]. The displacement of the body in 2 s is:

    A)  \[\frac{2\upsilon (n-1)}{n}\]

    B)  \[\frac{\upsilon (n-1)}{n}\]

    C)  \[\frac{\upsilon (n+1)}{n}\]

    D)  \[\frac{2\upsilon (n+1)}{n}\]

    Correct Answer: A

    Solution :

     Displacement in last 2 second \[=\frac{1}{2}a{{n}^{2}}-\frac{1}{2}a{{(n-2)}^{2}}\] \[=2a(n-1)\] Acceleration\[a=\frac{\upsilon }{n}\] \[(\because t=ns)\] Displacement in last \[2s=\frac{2\upsilon (n-1)}{n}\]


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