A) \[{{N}_{2}}O\]
B) \[NO\]
C) \[N{{H}_{4}}\]
D) \[N{{O}_{2}}\]
Correct Answer: A
Solution :
\[4Cu+10HN{{O}_{3}}\to 4Cu{{(N{{O}_{3}})}_{2}}+5{{H}_{2}}O+{{N}_{2}}O\]
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