A) 1 kg\[{{m}^{2}}\]
B) 0.1 kg\[{{m}^{2}}\]
C) 2 kg\[{{m}^{2}}\]
D) 0.2 kg\[{{m}^{2}}\]
Correct Answer: B
Solution :
The moment of inertia of the given system that contains 5 particles each of mass 2 kg on the rim of circular disc of radius 0.1 m and of negligible mass is .given by \[=MI\]of disc\[+MI\]of particles Since, the mass of the disc is negligible therefore, MI of the system\[=MI\]of particles \[=5\times 2\times {{(0.1)}^{2}}=0.1\,kg\,{{m}^{2}}\]
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