Manipal Medical Manipal Medical Solved Paper-2006

  • question_answer
    A closed organ pipe and an open organ pipe are tuned to the same fundamental frequency. What is the ratio of their lengths?

    A)  \[1:2\]           

    B)  \[2:1\]

    C)  \[2:3\]           

    D)  \[4:3\]

    Correct Answer: A

    Solution :

     Avoiding end correction, the length of closed organ pipe, is \[{{l}_{1}}=\frac{{{\lambda }_{1}}}{4}\]or\[{{\lambda }_{1}}=4{{l}_{1}}\] The length of open organ pipe, is \[{{l}_{2}}=\frac{{{\lambda }_{2}}}{2}\]or \[{{\lambda }_{2}}=2{{l}_{2}}\] Here,         \[{{n}_{1}}={{n}_{2}}\] \[\Rightarrow \] \[\frac{v}{{{\lambda }_{1}}}=\frac{v}{{{\lambda }_{2}}}\] Or \[\frac{v}{4{{l}_{1}}}=\frac{v}{2{{l}_{2}}}\] Therefore,   \[{{l}_{1}}:{{l}_{2}}=1:2\]


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