A) 30 kV
B) 50 kV
C) 80 kV
D) 60 Kv
Correct Answer: A
Solution :
From the formula \[eV=\frac{hc}{\lambda }\] \[V=\frac{hc}{e\lambda }\] \[=\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{9}}}{1.6\times {{10}^{-18}}\times 0.4125\times {{10}^{-10}}}\] \[=30\times {{10}^{3}}V=30\,kV\]
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