A) 165 Hz
B) 150 Hz
C) 660 Hz
D) 330 Hz
Correct Answer: C
Solution :
Phase difference of\[1.6\pi \]corresponds to path difference of 40 cm. Hence, phase difference of\[2\pi \]will correspond to a path difference of 50 cm, i.e.,\[K=50\]cm or 0.5 m. \[\therefore \] \[n=\frac{v}{\lambda }=\frac{330}{0.5}\] \[=660\text{ }Hz\]You need to login to perform this action.
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