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Manipal Medical Manipal Medical Solved Paper-2006

  • question_answer
    An L-C circuit is in the state of resonance. If \[C=0.1\mu F\]and\[L=0.25\text{ }H,\]neglecting ohmic resistance of circuit, what is the frequency of oscillations?

    A)  1007 Hz       

    B)  100 Hz

    C)  109 Hz         

    D)  500 Hz

    Correct Answer: A

    Solution :

     From the formula, the frequence of oscillation is \[f=\frac{1}{2\pi \sqrt{LC}}\] \[=\frac{1}{2\pi \sqrt{0.25\times 0.1\times {{10}^{-6}}}}\] \[\approx 1007\,Hz\]


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