A) 4.2 T
B) 2.8 T
C) 5.6 T
D) 8.4 T
Correct Answer: B
Solution :
Applying Keplers third law \[{{T}^{2}}\propto {{R}^{3}}\] Hence, \[{{\left( \frac{{{T}_{1}}}{{{T}_{2}}} \right)}^{2}}={{\left( \frac{{{R}_{1}}}{{{R}_{2}}} \right)}^{3}}={{\left( \frac{R}{2R} \right)}^{3}}\] \[\frac{T}{{{T}_{2}}}={{\left( \frac{1}{2} \right)}^{3/2}}\] \[{{T}_{2}}={{(2)}^{3/2}}T\] So, \[{{T}_{2}}=28T\]
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