A) \[3,2,1,\frac{1}{2}\]
B) \[3,1,1,-\frac{1}{2}\]
C) \[3,3,1,-\frac{1}{2}\]
D) \[3,2,-2,\frac{1}{2}\]
Correct Answer: C
Solution :
When\[n=3,\]number of values of I are 0 to\[n-1\] i.e, \[0,1,2.\] Hence, when\[n=3,\]then\[l=3\]does not exist.You need to login to perform this action.
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