A) \[C{{u}^{2+}}\]
B) \[C{{o}^{2+}}\]
C) \[C{{r}^{3+}}\]
D) \[Z{{n}^{2+}}\]
Correct Answer: D
Solution :
\[Z{{n}^{2+}}=3{{d}^{10}}4{{s}^{0}}\]has no unpaired electron hence, diamagnetic in nature.
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