Manipal Medical Manipal Medical Solved Paper-2007

  • question_answer
    In an octahedral structure, the pair of d orbitals involved in\[{{d}^{2}}s{{p}^{3}}\]hybridisation is

    A)  \[{{d}_{{{x}^{2}}-{{y}^{2}}}},{{d}_{{{z}^{2}}}}\]

    B)  \[{{d}_{xy}},{{d}_{{{x}^{2}}-{{y}^{2}}}}\]

    C)  \[{{d}_{{{z}^{2}}}},{{d}_{xz}}\]

    D)  \[{{d}_{xy}},{{d}_{yz}}\]

    Correct Answer: A

    Solution :

     In the formation of\[{{d}^{2}}s{{p}^{3}}\]hybrid orbitals, two \[(n-1)d\]orbitals of Cg. set ie,\[(n-1){{d}_{{{z}^{2}}}}\]and \[(n-1){{d}_{{{x}^{2}}-{{y}^{2}}}}\]orbitals, one ns and three rip \[(n{{p}_{x}},n{{p}_{y}}\]and\[n{{p}_{z}})\]orbitals combine together and form six\[{{d}^{2}}s{{p}^{3}}\]hybrid orbitals.


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