A) Proton accepted only
B) Both oxidised and reduced
C) Oxidised only
D) Reduced only
Correct Answer: B
Solution :
In reaction, \[{{H}_{2}}O+\overset{0}{\mathop{B}}\,{{r}_{2}}\xrightarrow[{}]{{}}HO\overset{+1}{\mathop{Br}}\,+H\overset{-1}{\mathop{Br}}\,\] The oxidation number of bromine increases from 0 to\[+1\]and decreases from 0 to\[-1,\]so due to this reason bromine is both oxidised as well as reduced in the above reaction.
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