A) \[981\text{ }cm/{{s}^{2}}\]
B) \[978\text{ }cm/{{s}^{2}}\]
C) \[984\text{ }cm/{{s}^{2}}\]
D) \[975\text{ }cm/{{s}^{2}}\]
Correct Answer: B
Solution :
\[{{L}_{1}}=\frac{{{g}_{1}}{{T}^{2}}}{4{{\pi }^{2}}}=\frac{{{g}_{1}}}{{{\pi }^{2}}};\] \[{{L}_{2}}=\frac{{{g}_{2}}{{T}^{2}}}{4{{\pi }^{2}}}=\frac{{{g}_{2}}}{{{\pi }^{2}}}\] Since, length is decreased,\[{{g}_{2}}\]is less than\[{{g}_{1}}\]. \[\therefore \] \[{{L}_{1}}-{{L}_{2}}=\frac{{{g}_{1}}-{{g}_{2}}}{{{\pi }^{2}}}\] Or \[({{L}_{1}}-{{L}_{2}}){{\pi }^{2}}={{g}_{1}}-{{g}_{2}}\] Or \[0.3\times 10={{g}_{1}}-{{g}_{2}}\] \[\therefore \] \[{{g}_{2}}=981-3=978\text{ }cm/{{s}^{2}}\]
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