A) ethyl formate
B) ethyl chlorofbrmate
C) acetyl chloride
D) carbon dioxide
Correct Answer: B
Solution :
Ethyl acetate is obtained when methyl magnesium bromide reacts with ethyl chloroformate. \[C{{H}_{3}}MgBr+Cl-\overset{\begin{smallmatrix} O \\ |\,| \end{smallmatrix}}{\mathop{C}}\,-O-{{C}_{2}}{{H}_{5}}\] \[\xrightarrow[{}]{{}}\left[ Cl-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} OMgBr \\ | \end{smallmatrix}}{\mathop{C}}}\,-O-{{C}_{2}}{{H}_{5}} \right]\] \[\downarrow \] \[\underset{Ethyl\text{ }acetate}{\mathop{C{{H}_{3}}-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-O-{{C}_{2}}{{H}_{5}}}}\,+MgBrCl\]
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