A) \[{{C}_{(diamond)}}+{{O}_{2}}(g)\xrightarrow[{}]{{}}C{{O}_{2}}(g)\]
B) \[\frac{1}{2}{{H}_{2}}(g)+\frac{1}{2}{{F}_{2}}(g)\xrightarrow[{}]{{}}HF(g)\]
C) \[{{N}_{2}}(g)+3{{H}_{2}}(g)\xrightarrow[{}]{{}}2N{{H}_{3}}(g)\]
D) \[CO(g)+\frac{1}{2}{{O}_{2}}(g)\xrightarrow[{}]{{}}C{{O}_{2}}(g)\]
Correct Answer: B
Solution :
\[\Delta H_{f}^{o}\]is the enthalpy change when 1 mol of the substance is formed from its elements in the standard state. Reaction [a] does not represent \[\Delta H_{f}^{o}\]because standard state of carbon is graphite and not diamond.
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