A) 0
B) 1
C) 2
D) 3
Correct Answer: B
Solution :
\[{{B}_{2}}:KK{{(\sigma 2s)}^{2}}{{({{\sigma }^{*}}2s)}^{2}}{{(\pi 2{{p}_{x}})}^{1}}{{(\pi 2{{p}_{y}})}^{1}}\] Bond order \[=\frac{1}{2}(4-2)=1\]
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